Generated Code
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C
C There are a total of 7 entries in the algebraic variable array.
C There are a total of 2 entries in each of the rate and state variable arrays.
C There are a total of 2 entries in the constant variable array.
C
C
C ALGBRC(1) is V in component environment (millivolt).
C VOI is t in component environment (millisec).
C STATES(1) is m in component sodium_channel_m_gate (dimensionless).
C STATES(2) is h in component sodium_channel_h_gate (dimensionless).
C CONSTS(1) is g_Na in component sodium_channel (milliS_per_cm2).
C CONSTS(2) is E_Na in component sodium_channel (millivolt).
C ALGBRC(2) is Na_conductance in component sodium_channel (milliS_per_cm2).
C ALGBRC(5) is i_Na in component sodium_channel (microA_per_cm2).
C ALGBRC(3) is alpha_m in component sodium_channel_m_gate (per_millisec).
C ALGBRC(6) is beta_m in component sodium_channel_m_gate (per_millisec).
C ALGBRC(4) is alpha_h in component sodium_channel_h_gate (per_millisec).
C ALGBRC(7) is beta_h in component sodium_channel_h_gate (per_millisec).
C RATES(1) is d/dt m in component sodium_channel_m_gate (dimensionless).
C RATES(2) is d/dt h in component sodium_channel_h_gate (dimensionless).
C
SUBROUTINE initConsts(CONSTS, RATES, STATES)
REAL CONSTS(*), RATES(*), STATES(*)
STATES(1) = 0.05
STATES(2) = 0.6
CONSTS(1) = 120
CONSTS(2) = 35
RETURN
END
SUBROUTINE computeRates(VOI, CONSTS, RATES, STATES, ALGBRC)
REAL VOI, CONSTS(*), RATES(*), STATES(*), ALGBRC(*)
ALGBRC(1) = TERNRY(VOI.GT.5.00000.AND.VOI.LT.15.0000, 0.00000, - 85.0000)
ALGBRC(3) = ( - 0.100000*(ALGBRC(1)+50.0000))/(EXP(- (ALGBRC(1)+50.0000)/10.0000) - 1.00000)
ALGBRC(6) = 4.00000*EXP(- (ALGBRC(1)+75.0000)/18.0000)
RATES(1) = ALGBRC(3)*(1.00000 - STATES(1)) - ALGBRC(6)*STATES(1)
ALGBRC(4) = 0.0700000*EXP(- (ALGBRC(1)+75.0000)/20.0000)
ALGBRC(7) = 1.00000/(EXP(- (ALGBRC(1)+45.0000)/10.0000)+1.00000)
RATES(2) = ALGBRC(4)*(1.00000 - STATES(2)) - ALGBRC(7)*STATES(2)
RETURN
END
SUBROUTINE computeVariables(VOI, CONSTS, RATES, STATES, ALGBRC)
REAL VOI, CONSTS(*), RATES(*), STATES(*), ALGBRC(*)
ALGBRC(1) = TERNRY(VOI.GT.5.00000.AND.VOI.LT.15.0000, 0.00000, - 85.0000)
ALGBRC(3) = ( - 0.100000*(ALGBRC(1)+50.0000))/(EXP(- (ALGBRC(1)+50.0000)/10.0000) - 1.00000)
ALGBRC(6) = 4.00000*EXP(- (ALGBRC(1)+75.0000)/18.0000)
ALGBRC(4) = 0.0700000*EXP(- (ALGBRC(1)+75.0000)/20.0000)
ALGBRC(7) = 1.00000/(EXP(- (ALGBRC(1)+45.0000)/10.0000)+1.00000)
ALGBRC(2) = CONSTS(1)*STATES(1) ** 3.00000*STATES(2)
ALGBRC(5) = ALGBRC(2)*(ALGBRC(1) - CONSTS(2))
RETURN
END
REAL FUNCTION TERNRY(TEST, VALA, VALB)
LOGICAL TEST
REAL VALA, VALB
IF (TEST) THEN
TERNRY = VALA
ELSE
TERNRY = VALB
ENDIF
RETURN
END
