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Model Mathematics

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Component: environment

Component: x1

Component: x2

\frac{d}{d time} (x2) = k1_x3 + k3_PTP x5 + k4_x6 - (k1 x1 x2 + k4 x2)

Component: x3

\frac{d}{d time} (x3) = k1 x1 x2 - (k1_x3 + k3 x3)

Component: x4

\frac{d}{d time} (x4) = k2 x1 x5 + k4b_x7 - (k2_x4 + k4b x4)

Component: x5

\frac{d}{d time} (x5) = k3 x3 + k2_x4 + k4b_x8 - (k2 x1 x5 + k3_PTP x5 + k4b x5)

Component: x6

\frac{d}{d time} (x6) = k5 + k6 PTP (x7 + x8) + k4 x2 - (k5_x6 + k4_x6)

Component: x7

\frac{d}{d time} (x7) = k4b x4 - (k4b_x7 + k6 PTP x7)

Component: x8

\frac{d}{d time} (x8) = k4b x5 - (k4b_x8 + k6 PTP x8)

Component: x9

\frac{d}{d time} (x9) = k7_PTP x10 - (\frac{k7 x9 (x4 + x5)}{IRp})

Component: x10

\frac{d}{d time} (x10) = \frac{k7 x9 (x4 + x5)}{IRp} + k8_x12 - ((k7_PTP + k8 x11) x10)

Component: x11

\frac{d}{d time} (x11) = k8_x12 - (k8 x10 x11)

Component: x12

\frac{d}{d time} (x12) = k8 x10 x11 - (k8_x12)

Component: x13

\frac{d}{d time} (x13) = k9 x14 + k10 x15 - ((k9_PTEN + k10_SHIP) x13)

Component: x14

\frac{d}{d time} (x14) = k9_PTEN x13 - (k9 x14)

Component: x15

\frac{d}{d time} (x15) = k10_SHIP x13 - (k10 x15)

Component: x16

\frac{d}{d time} (x16) = k11_x17 - (k11 x16)

Component: x17

\frac{d}{d time} (x17) = k11 x16 - (k11_x17)

Component: x18

\frac{d}{d time} (x18) = k12_x19 - (k12 x18)

Component: x19

\frac{d}{d time} (x19) = k12 x18 - (k12_x19)

Component: x20

\frac{d}{d time} (x20) = k13_x21 + k14 - ((k13 + k13b) x20 + k14_x20)

Component: x21

\frac{d}{d time} (x21) = k13_x21 - ((k13 + k13b) x20)

Component: reaction_constants

k2 = k1 k2_= 100.0 k1_k3_= k1_k4 = \frac{k4_}{9.0} k5 = \{\begin{matrix} 10.0 k5_if x6 + x7 + x8 > 1.0E-13 \\ 60.0 k5_otherwise \end{matrix} k7_= \frac{2.5}{7.45} k7 k8 = k8_\frac{5.0}{70.775} 1.0E12 k9 = (k9_stimulated - k9_basal) \frac{x12}{PI3K} + k9_basal k9_= \frac{94.0}{3.1} k9_stimulated k9_basal = \frac{0.31}{99.4} k9_k10 = \frac{3.1}{2.9} k10_k11 = 0.1 k11_\frac{x13 - 0.31}{3.10 - 0.31} k11_= 10.0 \ln 2.0 k12 = 0.1 k12_\frac{x13 - 0.31}{3.10 - 0.31} k12_= 10.0 \ln 2.0 k13 = \frac{4.0}{96.0} k13_k13b = (\frac{40.0}{60.0} - (\frac{4.0}{96.0})) k13_effect k14 = \frac{k14_}{96.0} effect = \frac{0.2 x17 + 0.8 x19}{APequil}

Source: Derived from workspace Sedaghat, Sherman, Quon, 2002 at changeset 29cb300949c4.; This exposure was expired. A more up-to-date exposure is available, or view related resources.

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A mathematical model of metabolic insulin signaling pathways